num-num,thousand of

Q1：thousand=num/1000%10; %10是什么意思？假如这个数是8842，结果会是什么？

除以10，余数是8。

Q2：thousand=num/1000%10; 假如这个数是8842,结果会是什么?

%10 是 除以10 求余 结果是8

Q3：C语言中将一个四位数的千位和个位对调

思路：分别得到这个四位数的千位、百位、十位、个位，结果等于个位*1000+百位*100+十位*10+千位代码为：#includeint main(){ int num = 2568; int thousand = num /1000; int hundred = num%1000/100; int ten = num%1000%100/10; int one = num%100%100%10; printf("原数字为：%d，转换后为：%d\n", num,one*1000+hundred*100+ten*10+thousand);} 运行结果：

Q4：C语言简单问题

#includemain(){ long num; int indiv,ten,hundred,thousand,ten_thousand,place; printf("Please input an integer:"); scanf("%ld",#); if(num>9999) place=5; else if(num>999) place=4; else if(num>99) place=3; else if(num>9) place=2; else place=1; printf("place=%d\n",place); printf("each digit is:"); ten_thousand=num/10000; thousand=(int)(num-ten_thousand*10000)/1000; hundred=(int)(num-ten_thousand*10000-thousand*1000)/100; ten=(int)(num-ten_thousand*10000-thousand*1000-hundred*100)/10; indiv=(int)(num-ten_thousand*10000-thousand*1000-hundred*100-ten*10); switch(place) { case 5: printf("%d,%d,%d,%d,%d",ten_thousand,thousand,hundred,ten,indiv); printf("\nReverse list is:"); printf("%d,%d,%d,%d,%d",indiv,ten,hundred,thousand,ten_thousand); break; case 4: printf("%d,%d,%d,%d",thousand,hundred,ten,indiv); printf("\nReverse list is:"); printf("%d,%d,%d,%d,%d",indiv,ten,hundred,thousand); break; case 3: printf("%d,%d,%d",hundred,ten,indiv); printf("\nReverse list is:"); printf("%d,%d,%d",indiv,ten,hundred); break; case 2: printf("%d,%d",ten,indiv); printf("\nReverse list is:"); printf("%d,%d",indiv,ten); break; case 1: printf("%d",indiv); printf("\nReverse list is:"); printf("%d",indiv); break; }}

Q5：在C语言环境下输入一个四位整数，求对应的数字并输出，最后千位和十位互换，百位

# include in change(int s){ int a，b，c，d，I；int ch[4]；a=(int)(s/1000)；b=(int)(s/100)；c=(int)(s/100)；d=(int)(s000)；\ *分隔输入数字的每个位，并分别将其分配给ABCD * \ ch[0]=c；ch[1]=d；ch[2]=a；ch[3]=b；\ *更改每个位上数字的顺序，并将它们存储在数组ch*\ s=0中；for(I=0；i4；I )\*此循环将分离位上的数字组合成一个完整的四位数* \ { s *=10s=ch[I]；}返回s；\ *返回结果* \ } void main(){ int in；printf("请输入数字\ n ")；scanf("%d "，in；);printf("您的答案是\ n ")；printf("%d\n "，change(in))；}/*该程序经过调试可以使用，得到正确的结果*/

Q6：C语言问题

# include " iostream。h " int reverse(int)；void main(){ printf(" 1234的反转是：%d\n "，反转(1234));} int reverse(int n) { int k=0，j；而(n0){ j=n；n=n/10；k=k * 10j}返回k；}