有问题就有答案
Q1：2,4,6,8,10用四则运算=100，加减乘除每种符号只能用一次
（2×4-6+8）×10=100
Q2：用2,4,10,10加减乘除四则运算列出算式，使得数为24,每个数只能使用一次。
(2 4/10)*10=24
Q3：两个10两个4可以用加减乘除法计算,每个符号只能用一次,最后怎样才能等于24
(1010-4)4=24
Q4：用2、3、－6、10（每数只能用一次）进行加减乘除，四则运算结果等于24
(2-10)*[3+(-6)]=24(2*3-10)*(-6)=24[10+(-6)]*3*2=243*[10-(-6)]/2=24
Q5：4,8,6,1如何用加减乘除计算得24（每个符号都得用到，每个只能用一次)
1: (8 - 4) 6 12: ((8 - 4) 6) 13: (8 - 4) (6 1)4: (8 - 4) 6 15: ((8 - 4) 6) 16: (8 - 4) (6 1) 7: (8 - 4) 1 68: (8 - 4 1) 69: ((8 - 4) 1) 610: (8 - (4 1)) 611: (8 - 4) (1 6)12: (8 - 4) 1 613: (8 - 4 1) 614: ((8 - 4) 1) 615: (8 - (4 1)) 616: (8 - 4) (1 6)17: 8 (6 - 4 1)18: 8 ((6 - 4) 1)19: 8 (6 - (4 - 1))20: 8 (6 1 - 4)21: 8 ((6 1) - 4)22: 8 (6 (1 - 4))23: (8 - 1 4) 624: (8 - (1 4)) 625: 8 (1 - 4 6)26: 8 ((1 - 4) 6)27: 8 (1 - (4 - 6))28: (8 1 - 4) 629: ((8 1) - 4) 630: (8 1 - 4) 631: ((8 1) - 4) 632: 8 (1 - 4 6)33: 8 (1 - (4 6))34: 8 (1 6 - 4)35: 8 ((1 6) - 4)36: 8 (1 (6 - 4)) 37: (6 - 4 1) 838: ((6 - 4) 1) 839: (6 - (4 - 1)) 840: (6 (8 - 4)) 141: 6 (8 - 4) 142: 6 (8 - 4 1) 43: 6 ((8 - 4) 1)44: 6 (8 - (4 1))45: (6 (8 - 4)) 146: 6 (8 - 4) 147: 6 (8 - 4 1)48: 6 ((8 - 4) 1) 49: 6 (8 - (4 1))50: 6 (8 - 1 4)51: 6 (8 - (1 4))52: 6 (8 1 - 4)53: 6 ((8 1) - 4)54: 6 (8 1 - 4) 55: 6 ((8 1) - 4)56: (6 1 - 4) 857: ((6 1) - 4) 858: (6 (1 - 4)) 859: 6 (1 8 - 4)60: 6 ((1 8) - 4) 61: 6 (1 (8 - 4))62: 6 1 (8 - 4)63: (6 1) (8 - 4)64: 6 1 (8 - 4)65: (6 1) (8 - 4)66: 6 (1 (8 - 4)) 67: (1 - 4 6) 868: ((1 - 4) 6) 869: (1 - (4 - 6)) 870: (1 8 - 4) 671: ((1 8) - 4) 672: (1 (8 - 4)) 673: 1 (8 - 4) 674: 1 ((8 - 4) 6)75: (1 6 - 4) 876: ((1 6) - 4) 877: (1 (6 - 4)) 878: 1 (6 (8 - 4))79: 1 6 (8 - 4)80: (1 6) (8 - 4)
Q6：负二四负六八组成算式,加减乘除括号。四个数都用,每个数只能用一次是运算结果
68(-2)(-4)=24 8-(-4)-6(-2)=24