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1+1+2+2+3+3+……………..99+99+100+1000

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Q1:1+1+2+2+3+3+……………..99+99+100+1000

如果你最后一个数是100则 (1+2+3+4+5………+100)×2={[(1+100)×100]/2}×2=10100如果你那是1000,在式子上加一百凑巧解,左边加了右边记得减去才和原式子统一。则在后面101000-100+1000=11000

Q2:1+1+2+2+3+3+4+4+5+5……99+99+100+100=?

(1+100)×100÷2×2如果不理解的话我来解释一下(1+100)×100÷2是根据前项与后项的和乘以项数除以2的公式,而再乘以二是因为所有的数都有两个(也就是说1有2个,2有2个……100有2个),所以要乘以2,本人解释得不太好,请谅解

Q3:1+1+2+2+3+3+4+4+5+5.+99+99+100+100等于多少

2(1 100)50=10100

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